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Part 7:
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Statistical Calculations |
Example 7.3a
Here we see the wages of a set of employees, grouped in intervals
of £50 (apart from the last one):
| Wages (£) |
100-150 |
150-200 |
200-250 |
250-300 |
300-350 |
350-400 |
400-500 |
| Frequency (f) |
17 |
25 |
34 |
47 |
26 |
15 |
3 |
Find the mean and standard deviation.
Solution:
The first interval thus emcompasses all wages between £100.00
and £149.99. A wage of £150.00 is included in the second
interval.
Consider the first interval. The 17 employees could all be earning
as much as £149.99 each or as little as £100.00 each,
we have no way of knowing. So, in order to make any calculations at
all, we have to make a fairly big assumption - that they all earn
an amount slap-bang in the middle of the interval, i.e. (100 + 150)
÷ 2 = £125.
The table now looks like this, the second
row (our x column) being the mid-values of each interval.
That the last inverval is different makes no odds, our last
mid-value just looks a bit different from the rest as well.
The calculations now follow:
|
| Wages |
Mid Value x |
f |
fx |
fx2 |
| 100-150 |
125 |
17 |
2,1150.0 |
268,750.00 |
| 150-200 |
175 |
25 |
4,375.0 |
765,625.00 |
| 200-250 |
225 |
34 |
7,650.0 |
1,721,250.00 |
| 250-300 |
275 |
47 |
12,925.0 |
3,554,375.00 |
| 300-350 |
325 |
26 |
8,450.0 |
2,746,250.00 |
| 350-400 |
375 |
15 |
5,625.0 |
2,109,375.00 |
| 400-500 |
450 |
3 |
1,350.0 |
607,500.00 |
| Totals |
|
167 |
42,525.0 |
11,773,125.00 |
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The mean wage of this group of employees is £254.49 per week,
and the wages are spread about so that, on average, the wages are
£75.59 away from the mean.
The real mean and standard deviation will be a bit different, of course,
but these figures will be close enough to be used in any further calculations
or discussions. |
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